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Calculation of Material Required For Brickwork
Today in this article we are going to learn how to calculate numbers of bricks in 1 Cum and how to calculate the quantity of cement and sand in brickwork.
Important Points For Estimation
Density of Cement = 1440 kg/ m3
Density of Sand = 1450 – 1500 kg/ m3
Density of Aggregate = 1450 – 1550 kg/ m3
Quantity or Weight of Cement in 1 Bag = 50 KG
The volume of 1 Bag Cement in Cum = 0.03472 cubic meter
The volume of 1 Bag Cement in Cft = 1.226 cubic feet
Numbers of Cement Bags in 1 cum = 28.8 nos.
How many Cft in 1 Cum = 35.31 cft
How to calculate Numbers of bricks in 1 Cubic Metre?
Size of brick varies according to the region. In India, the standard size of the brick is = 9″ x4″ x3″
Size of one Brick in inches = 9″ ×4″ × 3″
Size of 1 Brick in Metre = 9″×0.0254 × 4″×0.0254 × 3″×0.0254 (1 inch = 0.0254 m)
= 0.2286 × 0.1016 × 0.0762
The volume of 1 Brick = 0.001769 cum
Numbers of brick in 1 Cum = 1/0.001769
= 565.29 say 565 nos
Brickwork Calculation
Take a wall
Length of wall = 20 metre
Width of wall = 23 cm or 0.23 metre or 9″
Height of wall = 5 m
The volume of wall = L × B × H
= 20 × 0.23 × 5
= 23 cum
Normally mortar joints are less than 1 cm ( 10 to 16 mm ). Let’s consider it 10 mm or 0.39″.
Add 0.39″ in all face of brick excluding the front face.
Size of Brick = 9″ ×4″ × 3″
Add 0.39″ in each face = (9″+0.39 × 4″ +0.39 × 3″+0.39)
= 9.39″ ×4.39″ × 3.39″
The volume of Brick with Mortar = 9.39″ × 4.39″ × 3.39″
= (9.39″ × 0.0254) × (4.39″ × 0.0254) × (3.39″ × 0.0254) [ 1 inch = 0.0254 metre ]
= 0.238 × 0.111 × 0.086
= 0.002286 Cum
Number of Bricks in Wall = 23/0.002286
= 10061.24 say 10061 nos
Therefore, the number of bricks per cum of nominal size = Total nos of bricks in the wall/volume of wall
= 10061/23
= 437.43 say 437 nos. (approx)
Considering 5% breakages, wastages, etc., This may be taken 460 numbers per cubic metre.
Calculation of Quantity of Mortar in Brickwork
Mortar Requirement = Total volume of brickwork minus net volume of bricks
= 23 – (9″ × 4″ × 3″ × 10061)
= 23 – (0.2286 × 0.1016 × 0.0762 × 10061) [ 1 inch = 0.0254 m ]
= 23 – 17.797
= 5.2 cum
For frog filling, for use of cut brick, for bonding, for uniform joints, wastage, etc. 15% extra mortar may be required.
Therefore, the volume of mortar = 5.2 + 5.2 × 0.15
= 5.98 cum
For dry volume increase by 1/4
Dry volume of Mortar = 5.98 + 5.98 × 0.25
= 7.475 cum
For 23 cum of brickwork dry volume of mortar = 7.475 cum
For 1 cum dry volume of mortar = 7.475/23
= 0.325 cum or 11.47 cft ( 1 Cum = 35.31 cft )
In practice, for cement mortar 3 cum dry mortar and for lime mortar 3.5 cum of dry mortar are taken for 10 cum brickwork. As an approximate 30% dry mortar may be taken.
Calculation of Cement and Sand in Mortar
Approximate method to determine the quantity of materials of mortar for 1cum brickwork divide 0.3 by the sum of the numerals of the proportion of materials which gives the quantity of cement in cum.
Example – For brickwork in 1: 6 cement mortar = 0.3/ (1+6) = 0.043 cum
Cement = 0.043 × 28.8 = 1.238 bags ( Numbers of cement bags in 1 Cum = 28.8 )
Sand = 0.043 × 6 = 0.258 cum
But as the cement will go to fill up the voids in the sand, 0.045 cum of cement and 0.27 cum of sand may be taken.
I hope now you understood how to calculate quantity of materials in brickwork.
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Also, read
How to Calculate Quantity of Material For Plastering
How to Calculate Quantity of Materials For Concrete Mix Ratio
How to Calculate Unit Weight of Steel Bar?
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